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F(x)=3x^2-7x+4

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Answer to a math question F(x)=3x^2-7x+4

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Neal
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95 Answers
3x^{2}-7x+4=0
x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 3\times 4}}{2\times 3}
x=\frac{-\left(-7\right)±\sqrt{49-4\times 3\times 4}}{2\times 3}
x=\frac{-\left(-7\right)±\sqrt{49-12\times 4}}{2\times 3}
x=\frac{-\left(-7\right)±\sqrt{49-48}}{2\times 3}
x=\frac{-\left(-7\right)±\sqrt{1}}{2\times 3}
x=\frac{-\left(-7\right)±1}{2\times 3}
x=\frac{7±1}{2\times 3}
x=\frac{7±1}{6}
x=\frac{8}{6}
x=\frac{4}{3}
x=\frac{6}{6}
x=1
3x^{2}-7x+4=3\left(x-\frac{4}{3}\right)\left(x-1\right)
3x^{2}-7x+4=3\times \left(\frac{3x-4}{3}\right)\left(x-1\right)
3x^{2}-7x+4=\left(3x-4\right)\left(x-1\right)

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