Question
Find the equation of a circle satisfying the condition given (3,-8) radius 9
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Answer to a math question Find the equation of a circle satisfying the condition given (3,-8) radius 9
Sigrid
4.5119 Answers
1. The general equation of a circle with center \((h, k)\) and radius \(r\) is:
(x - h)^2 + (y - k)^2 = r^2
2. Given the center of the circle is \((3, -8)\), so:
h = 3, \quad k = -8
3. The radius \(r\) is 9, so:
r = 9
4. Substitute \(h\), \(k\), and \(r\) into the general equation:
(x - 3)^2 + (y + 8)^2 = 9^2
5. Simplify the right side:
9^2 = 81
6. Therefore, the equation of the circle is:
(x - 3)^2 + (y + 8)^2 = 81
Answer:
(x - 3)^2 + (y + 8)^2 = 81
2. Given the center of the circle is \((3, -8)\), so:
3. The radius \(r\) is 9, so:
4. Substitute \(h\), \(k\), and \(r\) into the general equation:
5. Simplify the right side:
6. Therefore, the equation of the circle is:
Answer:
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