Find the equation of a circle satisfying the condition given (3,-8) radius 9

1. The general equation of a circle with center \((h, k)\) and radius \(r\) is:
(x - h)^2 + (y - k)^2 = r^2

2. Given the center of the circle is \((3, -8)\), so:
h = 3, \quad k = -8

3. The radius \(r\) is 9, so:
r = 9

4. Substitute \(h\), \(k\), and \(r\) into the general equation:
(x - 3)^2 + (y + 8)^2 = 9^2

5. Simplify the right side:
9^2 = 81

6. Therefore, the equation of the circle is:
(x - 3)^2 + (y + 8)^2 = 81

Answer:
(x - 3)^2 + (y + 8)^2 = 81