Answer: \frac{(x+5)}{3} Step-by-step solution, Assume f\left(x\right)=y So y=3x-5 and x=\frac{\left(y+5\right)}{3} So x=\frac{\left(f\left(x\right)+5\right)}{3} So inverse function is \frac{\left(x+5\right)}{3}
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What is the limit of (2x^2 + 3x + 1) / (x^3 + 2x^2 + x + 1) as x approaches positive infinity?