Answer: \frac{(x+5)}{3} Step-by-step solution, Assume f\left(x\right)=y So y=3x-5 and x=\frac{\left(y+5\right)}{3} So x=\frac{\left(f\left(x\right)+5\right)}{3} So inverse function is \frac{\left(x+5\right)}{3}
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Question: What is the definite integral of f(x) = 2x^3 - 4x^2 + 3x - 1 from x = -1 to x = 3?