Question
Fine the vertex, focus and directrix of Y+7=1/12(x-6)^2
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Answer to a math question Fine the vertex, focus and directrix of Y+7=1/12(x-6)^2
Fred
4.4118 Answers
1. The given equation is in the form y + 7 = \frac{1}{12}(x - 6)^2
2. Convert it to the standard form of a parabolay - k = \frac{1}{4p}(x - h)^2 (h, k)
- Here,k = -7 h = 6 \frac{1}{4p} = \frac{1}{12}
3. Calculate [Step-by-Step]p = 3
Vertex:(6, -7)
Focus: The focus is at(h, k + p) (6,-7+3)=(6,-4)
Directrix: The directrix is aty = k - p y=-7-3=-10
Answer:
Vertex:(6, -7)
Focus:(6,-4)
Directrix:y=-10
2. Convert it to the standard form of a parabola
- Here,
3. Calculate [Step-by-Step]
Vertex:
Focus: The focus is at
Directrix: The directrix is at
Answer:
Vertex:
Focus:
Directrix:
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