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From a lighthouse 15 meters above sea level, a shipwreck can be seen on the sea surface 100 meters away at the foot of the lighthouse. What is the angle of depression from the top of the lighthouse to the wreck?

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Answer to a math question From a lighthouse 15 meters above sea level, a shipwreck can be seen on the sea surface 100 meters away at the foot of the lighthouse. What is the angle of depression from the top of the lighthouse to the wreck?

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Murray
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Para encontrar el ángulo de depresión desde lo alto del faro hasta el naufragio, podemos usar la fórmula de la tangente de un ángulo en un triángulo rectángulo: \tan(\theta) = \frac{\text{opuesto}}{\text{adyacente}} En este escenario: - El lado **opuesto** es el desnivel vertical desde el faro hasta el pecio, que es de **15 metros**. - El lado **adyacente** es la distancia horizontal desde el faro hasta el pecio, que es de **100 metros**. Entonces, la fórmula queda: \tan(\theta) = \frac{15}{100} Para encontrar el ángulo de depresión, \( \theta \), tomamos la tangente inversa (arctan) de la razón: \theta = \arctan\left(\frac{15}{100}\right) Usando una calculadora para encontrar la tangente inversa, obtenemos: \theta \aprox \arctan(0.15) \theta \aproximadamente 8,53^\circ Por lo tanto, el ángulo de depresión desde la cima del faro hasta el naufragio es de aproximadamente **8,53 grados**.

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