Question

Given is the polynomial f of xx^2+ px+q, where p,q are arbitrary real numbers. The zeros of a function d of x are defined as the values x0 for which f of x0 is 0. For which values of fx does it have a zero?

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Answer to a math question Given is the polynomial f of xx^2+ px+q, where p,q are arbitrary real numbers. The zeros of a function d of x are defined as the values x0 for which f of x0 is 0. For which values of fx does it have a zero?

$Expert avatar$

Corbin

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108 Answers

1. Gegeben ist die quadratische Funktion

f(x) = x^2 + px + q

.
2. Die Nullstellen einer Funktion finden wir, indem wir

f(x) = 0

setzen:

x^2 + px + q = 0

.
3. Die quadratische Gleichung hat reale Lösungen, wenn die Diskriminante

\Delta = p^2 - 4q \geq 0

ist.
4. Daher existieren reelle Nullstellen der Funktion

f(x)

für die Werte von

, wenn

p^2 - 4q \geq 0

gilt.

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Given is the polynomial f of xx^2+ px+q, where p,q are arbitrary real numbers. The zeros of a function d of x are defined as the values x0 for which f of x0 is 0. For which values of fx does it have a zero?

Answer to a math question Given is the polynomial f of xx^2+ px+q, where p,q are arbitrary real numbers. The zeros of a function d of x are defined as the values x0 for which f of x0 is 0. For which values of fx does it have a zero?

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