\text{1. Define variables for average speeds:}
v_f \text{ for the front trip and } v_r \text{ for the return trip.}
\text{2. Given that the return trip took half the time of the front trip:}
t_r = \frac{t_f}{2}
\text{3. Use the relationship between distance, speed, and time:}
d = v_f \cdot t_f \quad \text{(front trip)}
d = v_r \cdot t_r \quad \text{(return trip)}
\text{4. Since the distances are equal:}
v_f \cdot t_f = v_r \cdot \frac{t_f}{2}
\text{5. Simplify to find the relationship between the speeds:}
v_f = \frac{v_r}{2} \Rightarrow v_r = 2v_f
\text{6. Therefore, the average speed on the return trip is twice the average speed on the front trip:}
v_r = 2v_f