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if the wheel of the bicycle in the previous problem turns at a constant rate of 2.5 revolutions per second, what is the linear speed in feet per second

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Answer to a math question if the wheel of the bicycle in the previous problem turns at a constant rate of 2.5 revolutions per second, what is the linear speed in feet per second

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Lurline
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108 Answers
Solution:
1. Given:
- Rate of revolutions: 2.5 revolutions per second

2. Find the linear speed:
- Linear speed is given by the formula: v = r \cdot \omega where v is the linear speed, r is the radius of the wheel, and \omega is the angular speed.
- Angular speed in radians per second: \omega = 2\pi \times 2.5 = 5\pi radians per second

3. Recalculate considering the wheel radius from previous problem:
- Let’s assume the radius of the wheel is r feet. Since the problem does not provide the radius, you might need to know the radius from a previous problem.

4. Linear speed calculation:
v = r \cdot 5\pi \, \text{{feet per second}}

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