In the battery has an output of 12v, and the current measurement is 2a, calculate the watts of power dissipated in the light bulb

We use the formula for electrical power:

1. Identify given values:
- Voltage (V): 12 \, \text{V}
- Current (I): 2 \, \text{A}

2. Use the formula for power:
P = V \times I

3. Substitute the given values:
P = 12 \, \text{V} \times 2 \, \text{A} = 24 \, \text{W}

Answer: 24 \, \text{W}