Question
Let f: R -> R ; A f (x+1) = 2 f (x) - 5 and f (0) = 6, what is the value of f (2)?
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Answer to a math question Let f: R -> R ; A f (x+1) = 2 f (x) - 5 and f (0) = 6, what is the value of f (2)?
Frederik
4.6101 Answers
1. Start with the initial condition:
f(0) = 6
2. Use the recurrence relation to find f(1), letting x=0:
f(1) = 2f(0) - 5 = 2 \cdot 6 - 5 = 12 - 5 = 7
3. Use the recurrence relation again to find f(2), letting x=1:
f(2) = 2f(1) - 5 = 2 \cdot 7 - 5 = 14 - 5 = 9
Thus, the value of f(2) is:
f(2) = 9
2. Use the recurrence relation to find f(1), letting x=0:
3. Use the recurrence relation again to find f(2), letting x=1:
Thus, the value of f(2) is:
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