Lists the intercepts of the following equation. 9x^2+4y^2=36

1. Find the x-intercepts:
- Set \( y = 0 \) in \( 9x^2 + 4y^2 = 36 \):
9x^2 + 4(0)^2 = 36
9x^2 = 36
x^2 = 4
x = \pm 2
- Hence, the x-intercepts are (\pm 2, 0) .

2. Find the y-intercepts:
- Set \( x = 0 \) in \( 9x^2 + 4y^2 = 36 \):
9(0)^2 + 4y^2 = 36
4y^2 = 36
y^2 = 9
y = \pm 3
- Hence, the y-intercepts are (0, \pm 3) .

Therefore, the intercepts are:
- x-intercepts: (\pm 2, 0)
- y-intercepts: (0, \pm 3)