Apply the fraction rule $\frac{a}{c}-\frac{b}{c}=\frac{a-b}{c}$
$=\frac{x(x-1)-3(x+1)}{(x+1)(x-1)^{2}}$
Simplify $x(x-1)-3(x+1):{\quad}x^{2}-4x-3$
$=\frac{x^{2}-4x-3}{(x+1)(x-1)^{2}}$
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