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rosa can jog 5 mi downhill in the same time it takes her 3 mi to jog uphil she jogs 4mi faster downhill than uphill what i

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ROSA CAN JOG 5 MI DOWNHILL IN THE SAME TIME IT TAKES HER 3 MI TO JOG UPHIL. SHE JOGS 4MI FASTER DOWNHILL THAN UPHILL. WHAT IS HER JOGGING RATE EACH WAY

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Answer to a math question ROSA CAN JOG 5 MI DOWNHILL IN THE SAME TIME IT TAKES HER 3 MI TO JOG UPHIL. SHE JOGS 4MI FASTER DOWNHILL THAN UPHILL. WHAT IS HER JOGGING RATE EACH WAY

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Solution: let the uphill speed = x downhill speed will be = x+4 time = distance/speed time to jog 3 MI uphill = 3/x time to jog 5 MI uphill = 5/(x+4) as per given, both time are same. so, \frac{3}{x}=\frac{5}{\left(x+4\right)}\xrightarrow{}3\left(x+4\right)=5x\xrightarrow{}3x+12=5x

12=5x-3x\xrightarrow{}12=2x\xrightarrow{}2x=12

x=\frac{12}{2}\xrightarrow{}x=6 hence, uphill jogging rate = 6 mi/unit of time downhill jogging rate = 6+4 = 10 mi/unit of time

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