The area of the triangle below is 1/48.what is the length of the base? express your fraction in simplest form. The height is 1/6



Answer to a math question The area of the triangle below is 1/48.what is the length of the base? express your fraction in simplest form. The height is 1/6

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The area \(A\) of a triangle can be calculated using the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] Given that the area \(A = \frac{1}{48}\) and the height \(h = \frac{1}{6}\), we can substitute these values into the formula and solve for the base: \[ \frac{1}{48} = \frac{1}{2} \times \text{base} \times \frac{1}{6} \] First, multiply both sides by \(2\) to get rid of the \(\frac{1}{2}\) fraction: \[ \frac{1}{48} \times 2 = \text{base} \times \frac{1}{6} \] \[ \frac{2}{48} = \frac{\text{base}}{6} \] \[ \frac{1}{24} = \frac{\text{base}}{6} \] Now, multiply both sides by \(6\) to solve for the base: \[ \frac{1}{24} \times 6 = \text{base} \] \[ \frac{1}{4} = \text{base} \] So, the length of the base is \(\frac{1}{4}\).

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