Question
The weight of a person is given by the equation: -125+7x -4x +5(x+1)=7(x+5)+15 where x is the exact weight of this person and for his health the doctor recommended he lose 30% of his weight How many kg do you have to lose? If you manage to lose 30% of your weight, what would your current weight be?
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Answer to a math question The weight of a person is given by the equation: -125+7x -4x +5(x+1)=7(x+5)+15 where x is the exact weight of this person and for his health the doctor recommended he lose 30% of his weight How many kg do you have to lose? If you manage to lose 30% of your weight, what would your current weight be?
Miles
4.9109 Answers
1. Solve the equation for the exact weight x
-125 + 7x - 4x + 5(x+1) = 7(x+5) + 15
Simplify:
-125 + 8x + 5 = 7x + 50
Combine like terms:
-120 + 8x = 7x + 50
Isolate x
x = 170
His actual weight was 170 kg
2. Calculate 30% of the weight:
0.30 \times 170 = 51 \text{ kg}
He needs to loose 51 kg
3. Subtract the weight to lose from the original weight:
170 - 51 = 119 \text{ kg}
His current weight after loosing 30% weight is 119 kg
So you need to lose 51 kg, and your new weight would be 119 kg.
Simplify:
Combine like terms:
Isolate
His actual weight was
2. Calculate 30% of the weight:
He needs to loose
3. Subtract the weight to lose from the original weight:
His current weight after loosing 30% weight is
So you need to lose 51 kg, and your new weight would be 119 kg.
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