Question

The weight of a person is given by the equation: -125+7x -4x +5(x+1)=7(x+5)+15 where x is the exact weight of this person and for his health the doctor recommended he lose 30% of his weight How many kg do you have to lose? If you manage to lose 30% of your weight, what would your current weight be?

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Answer to a math question The weight of a person is given by the equation: -125+7x -4x +5(x+1)=7(x+5)+15 where x is the exact weight of this person and for his health the doctor recommended he lose 30% of his weight How many kg do you have to lose? If you manage to lose 30% of your weight, what would your current weight be?

$Expert avatar$

Miles

4.9

110 Answers

1. Solve the equation for the exact weight

-125 + 7x - 4x + 5(x+1) = 7(x+5) + 15

Simplify:

-125 + 8x + 5 = 7x + 50

Combine like terms:

-120 + 8x = 7x + 50

Isolate

x = 170

His actual weight was

170 kg

2. Calculate 30% of the weight:

0.30 \times 170 = 51 \text{ kg}

He needs to loose

51 kg

3. Subtract the weight to lose from the original weight:

170 - 51 = 119 \text{ kg}

His current weight after loosing 30% weight is

119 kg

So you need to lose 51 kg, and your new weight would be 119 kg.

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The weight of a person is given by the equation: -125+7x -4x +5(x+1)=7(x+5)+15 where x is the exact weight of this person and for his health the doctor recommended he lose 30% of his weight How many kg do you have to lose? If you manage to lose 30% of your weight, what would your current weight be?

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