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Solved equation
4x^2-16x=0
Theta=arcos ((9)/(15))
f(x)=x^2+1,g(x)=2x-2,h(x)=-x-1
x^2-4=0
105226549/25000000-3
y=4x+8
(0.8)/(75)
y=sqrt(5x+10)+19
536-412/8-6
(2x+16)=96
