2. To solve for x, first isolate the x term by subtracting 3y from both sides: 2x = 9 - 3y
3. Divide both sides by 2 to solve for x: x = \frac{9 - 3y}{2}
Frequently asked questions (FAQs)
Which rule states that if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent?
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What is the limit of (3x^2 + 2x - 5) as x approaches 4?