1. Start with the system of equations:
4x + 3y = 3
5x + 3y = 6
2. Subtract the first equation from the second to eliminate \( y \):
(5x + 3y) - (4x + 3y) = 6 - 3
Simplifying gives:
x = 3
3. Substitute \( x = 3 \) into the first equation:
4(3) + 3y = 3
12 + 3y = 3
4. Solve for \( y \):
3y = 3 - 12
3y = -9
y = -3
5. Therefore, the solution is:
x = 3, \, y = -3