Question
A body of mass 3kg is subjected to the action of two forces of 6N and 4N arranged perpendicularly. determine the total force applied
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Answer to a math question A body of mass 3kg is subjected to the action of two forces of 6N and 4N arranged perpendicularly. determine the total force applied
Hermann
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1. Given two perpendicular forces:
F_1 = 6\, \text{N}
F_2 = 4\, \text{N}
2. Use the Pythagorean theorem to find the total force:
F_{\text{total}} = \sqrt{F_1^2 + F_2^2}
3. Substitute the values:
F_{\text{total}} = \sqrt{6^2 + 4^2}
F_{\text{total}} = \sqrt{36 + 16}
F_{\text{total}} = \sqrt{52}
F_{\text{total}} = 2\sqrt{13} \, \text{N}
Answer:
2\sqrt{13} \, \text{N}
2. Use the Pythagorean theorem to find the total force:
3. Substitute the values:
Answer:
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