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A cylinder contains gas at a pressure of 3 atm and a volume of 6 L. If the pressure is decreased to 1 atm, what will be the new volume of the gas, assuming the temperature remains constant?

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Answer to a math question A cylinder contains gas at a pressure of 3 atm and a volume of 6 L. If the pressure is decreased to 1 atm, what will be the new volume of the gas, assuming the temperature remains constant?

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Bud
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1. Start with Boyle's Law: P_1 V_1 = P_2 V_2
2. Substitute known values: 3 \text{ atm} \cdot 6 \text{ L} = 1 \text{ atm} \cdot V_2
3. Solve for \( V_2 \): V_2 = \frac{3 \text{ atm} \cdot 6 \text{ L}}{1 \text{ atm}}
4. Compute the value of \( V_2 \): V_2 = 18 \text{ L}

Answer: V_2 = 18 \text{ L}

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