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A cylinder contains gas at a pressure of 3 atm and a volume of 6 L. If the pressure is decreased to 1 atm, what will be the new volume of the gas, assuming the temperature remains constant?

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Answer to a math question A cylinder contains gas at a pressure of 3 atm and a volume of 6 L. If the pressure is decreased to 1 atm, what will be the new volume of the gas, assuming the temperature remains constant?

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Bud

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97 Answers

1. Start with Boyle's Law:

P_1 V_1 = P_2 V_2

2. Substitute known values:

3 \text{ atm} \cdot 6 \text{ L} = 1 \text{ atm} \cdot V_2

3. Solve for $ V_2 $:

V_2 = \frac{3 \text{ atm} \cdot 6 \text{ L}}{1 \text{ atm}}

4. Compute the value of $ V_2 $:

V_2 = 18 \text{ L}

Answer:

V_2 = 18 \text{ L}

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A cylinder contains gas at a pressure of 3 atm and a volume of 6 L. If the pressure is decreased to 1 atm, what will be the new volume of the gas, assuming the temperature remains constant?

Answer to a math question A cylinder contains gas at a pressure of 3 atm and a volume of 6 L. If the pressure is decreased to 1 atm, what will be the new volume of the gas, assuming the temperature remains constant?

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