Question

A NaOH titrant solution with 2 grams of NaOH in 100mL where the Volume is 40mL, was used to determine the concentration of HCl acid (analyte solution) where the volume = 20mL. Calculate the concentration of HCl acid analyte solution in mol/L. Present your solution in mol/L to 1 significant figure. Enter a numeric value only without the mol/L unit.

191

likes955 views

Birdie

4.5

53 Answers

Given:

- Mass of NaOH = 2 grams

- Volume of NaOH solution = 100 mL = 0.1 L

- Volume of HCl solution = 20 mL = 0.02 L

- Volume of NaOH titrant solution = 40 mL = 0.04 L

1. Calculate moles of NaOH:

\text{Moles of NaOH} = \frac{2 \, \text{g}}{40 \, \text{g/mol}} = 0.05 \, \text{mol}

2. Calculate the molarity of NaOH (M_1 ):

M_1 = \frac{0.05 \, \text{mol}}{0.1 \, \text{L}} = 0.5 \, \text{mol/L}

3. Use the titration formula to find the molarity of the HCl solution (M_2 ):

M_1V_1 = M_2V_2

0.5 \, \text{mol/L} \times 0.04 \, \text{L} = M_2 \times 0.02 \, \text{L}

M_2 = \frac{0.5 \times 0.04}{0.02} = 1.0 \, \text{mol/L}

Therefore, the concentration of the HCl acid analyte solution is approximately\bf{1.0} mol/L (rounded to 1 significant figure).

\boxed{1.0}

- Mass of NaOH = 2 grams

- Volume of NaOH solution = 100 mL = 0.1 L

- Volume of HCl solution = 20 mL = 0.02 L

- Volume of NaOH titrant solution = 40 mL = 0.04 L

1. Calculate moles of NaOH:

2. Calculate the molarity of NaOH (

3. Use the titration formula to find the molarity of the HCl solution (

Therefore, the concentration of the HCl acid analyte solution is approximately

Frequently asked questions (FAQs)

What is the measure of angle A in a triangle if angle B = 45 degrees and angle C = 90 degrees?

+

Math question: Simplify the expression 3(x + 4) - 2(2x - 5) using the distributive property and factoring.

+

What is the sum of vector A (4, -3) and vector B (-2, 5)?

+

New questions in Mathematics