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A patient weights 223lbs and is put on a diet to lose 28 lns in 3 months. The patient loses 6 3/4 lbs the first month and 12 5/8 lbs the second month. How much weight must be lost in the 3rd month to reach his goal?

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Answer to a math question A patient weights 223lbs and is put on a diet to lose 28 lns in 3 months. The patient loses 6 3/4 lbs the first month and 12 5/8 lbs the second month. How much weight must be lost in the 3rd month to reach his goal?

Expert avatar
Eliseo
4.6
111 Answers
1. Convert first month's loss to improper fraction: 6 \frac{3}{4} = \frac{27}{4}

2. Convert second month's loss to improper fraction: 12 \frac{5}{8} = \frac{101}{8}

3. Convert \frac{27}{4} to \frac{54}{8} to add with \frac{101}{8} .

4. Total loss after two months: \frac{54}{8} + \frac{101}{8} = \frac{155}{8}

5. Total target loss is 28 lbs = \frac{224}{8}

6. Weight to lose in third month: \frac{224}{8} - \frac{155}{8} = \frac{69}{8}

7. Convert \frac{69}{8} to the mixed number: 8 \frac{5}{8}

Answer: 8\frac{5}{8}=8.625 lbs.

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