Question
A patient weights 223lbs and is put on a diet to lose 28 lns in 3 months. The patient loses 6 3/4 lbs the first month and 12 5/8 lbs the second month. How much weight must be lost in the 3rd month to reach his goal?
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Answer to a math question A patient weights 223lbs and is put on a diet to lose 28 lns in 3 months. The patient loses 6 3/4 lbs the first month and 12 5/8 lbs the second month. How much weight must be lost in the 3rd month to reach his goal?
Eliseo
4.6111 Answers
1. Convert first month's loss to improper fraction: 6 \frac{3}{4} = \frac{27}{4}
2. Convert second month's loss to improper fraction: 12 \frac{5}{8} = \frac{101}{8}
3. Convert \frac{27}{4} \frac{54}{8} \frac{101}{8}
4. Total loss after two months: \frac{54}{8} + \frac{101}{8} = \frac{155}{8}
5. Total target loss is 28 lbs = \frac{224}{8}
6. Weight to lose in third month: \frac{224}{8} - \frac{155}{8} = \frac{69}{8}
7. Convert \frac{69}{8} 8 \frac{5}{8}
Answer:8\frac{5}{8}=8.625
2. Convert second month's loss to improper fraction:
3. Convert
4. Total loss after two months:
5. Total target loss is 28 lbs =
6. Weight to lose in third month:
7. Convert
Answer:
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