. Calculate the number of moles, the number of formula units and the molarity of the solution that results from dissolving 30 grams of sulfuric acid in 800 milliliters of water.

1. **Find the number of moles of sulfuric acid (\text{H}_2\text{SO}_4).**

- Molar mass of \text{H}_2\text{SO}_4:

2 \times \text{H} + 1 \times \text{S} + 4 \times \text{O} = 2(1.01) + 32.07 + 4(16.00) = 98.09 \, \text{g/mol}

- Number of moles:

\frac{30 \, \text{g}}{98.09 \, \text{g/mol}} = 0.306 \, \text{mol}

2. **Calculate the number of formula units.**

- Avogadro's number: 6.022 \times 10^{23} \, \text{units/mol}

- Number of formula units:

0.306 \, \text{mol} \times 6.022 \times 10^{23} \, \text{units/mol} = 1.84 \times 10^{23} \, \text{formula units}

3. **Determine the molarity of the solution.**

- Convert volume from milliliters to liters:

800 \, \text{mL} = 0.800 \, \text{L}

- Calculate the molarity:

\frac{0.306 \, \text{mol}}{0.800 \, \text{L}} = 0.382 \, \text{M}

4. **Answer:**

- Number of moles: 0.306 \, \text{mol}
- Number of formula units: 1.84 \times 10^{23}
- Molarity: 0.382 \, \text{M}