Describe how you would prepare 1.0 L of a 0.10 M solution of acetic acid from 2.0 M solution of acetic acid

1. Identify the given values and the formula, \( C_1 = 2.0 \, \text{M} \), \( C_2 = 0.10 \, \text{M} \), and \( V_2 = 1.0 \, \text{L} \).
2. Use the dilution formula: C_1V_1 = C_2V_2
3. Substitute the given values: 2.0 \, \text{M} \times V_1 = 0.10 \, \text{M} \times 1.0 \, \text{L}
4. Solve for \( V_1 \):
V_1 = \frac{0.10 \, \text{M} \times 1.0 \, \text{L}}{2.0 \, \text{M}}
5. Calculate \( V_1 \):
V_1 = 0.050 \, \text{L}
6. Convert \( V_1 \) to milliliters if required:
V_1 = 50 \, \text{mL}
7. Conclusion: 50 mL of the 2.0 M acetic acid solution is needed to prepare the 1.0 L of 0.10 M solution.