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Describe how you would prepare 1.0 L of a 0.10 M solution of acetic acid from 2.0 M solution of acetic acid

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Answer to a math question Describe how you would prepare 1.0 L of a 0.10 M solution of acetic acid from 2.0 M solution of acetic acid

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Jayne

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1. Identify the given values and the formula, $ C_1 = 2.0 \, \text{M} $, $ C_2 = 0.10 \, \text{M} $, and $ V_2 = 1.0 \, \text{L} $.
2. Use the dilution formula:

C_1V_1 = C_2V_2

3. Substitute the given values:

2.0 \, \text{M} \times V_1 = 0.10 \, \text{M} \times 1.0 \, \text{L}

4. Solve for $ V_1 $:

V_1 = \frac{0.10 \, \text{M} \times 1.0 \, \text{L}}{2.0 \, \text{M}}

5. Calculate $ V_1 $:

V_1 = 0.050 \, \text{L}

6. Convert $ V_1 $ to milliliters if required:

V_1 = 50 \, \text{mL}

7. Conclusion: 50 mL of the 2.0 M acetic acid solution is needed to prepare the 1.0 L of 0.10 M solution.

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Describe how you would prepare 1.0 L of a 0.10 M solution of acetic acid from 2.0 M solution of acetic acid

Answer to a math question Describe how you would prepare 1.0 L of a 0.10 M solution of acetic acid from 2.0 M solution of acetic acid

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