Question

Determine the force with which two magnetic poles are attracted, one north of two webers and one 5 of eight webers separated 40 cm in a vacuum.

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Answer to a math question Determine the force with which two magnetic poles are attracted, one north of two webers and one 5 of eight webers separated 40 cm in a vacuum.

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Corbin
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106 Answers
La fuerza de atracción o repulsión entre dos polos magnéticos puede determinarse mediante la ley de Ampère, que establece que la fuerza magnética entre dos polos es directamente proporcional al producto de sus intensidades magnéticas y inversamente proporcional al cuadrado de la distancia que los separa.

La fórmula para calcular la fuerza entre dos polos magnéticos es:

F = \dfrac{\mu_0 \cdot m_1 \cdot m_2}{4\pi \cdot d^2}

Donde:
- F es la fuerza magnética,
- \mu_0 es la permeabilidad magnética del vacío ( 4\pi \times 10^{-7} \, T \cdot m/A ),
- m_1 y m_2 son las intensidades magnéticas de los polos (en webers),
- d es la distancia que los separa (en metros).

Dado que los dos polos tienen intensidades magnéticas de 2 y 8 webers, respectivamente, y están separados por 40 cm (0.4 m) en el vacío, podemos sustituir estos valores en la fórmula para calcular la fuerza:

F = \dfrac{(4\pi \times 10^{-7} \, T \cdot m/A) \cdot 2 \, Wb \cdot 8 \, Wb}{4\pi \cdot (0.4 \, m)^2}

Simplificando la expresión, obtenemos:

F = \dfrac{16 \times 10^{-7} \, T \cdot m \cdot Wb}{0.16 \, m^2}

F = 0.1 \, N

Entonces, la fuerza con la que se atraen los dos polos magnéticos es de 0.1 N.

\textbf{Respuesta:} La fuerza de atracción entre los dos polos magnéticos es de 0.1 N.

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