Establish a linear equation that expresses the relationship between temperature in degrees Celsius, C, and degrees Kelvin, K. Use the fact that water freezes at 0o Celsius (273.15 Kelvin) and boils at 100o Celsius (373.15 Kelvin).

Let's use the two data points provided to establish a linear equation relating Celsius temperature, C, to Kelvin temperature, K.

Given data points:
1. Water freezes at 0^\circ C which is 273.15 Kelvin.
2. Water boils at 100^\circ C which is 373.15 Kelvin.

Let's find the slope, m, of the linear equation using the two points:
m = \frac{K_2 - K_1}{C_2 - C_1} = \frac{373.15 - 273.15}{100 - 0} = \frac{100}{100} = 1

Now that we have the slope, we can write the point-slope form of a linear equation:
K - K_1 = m(C - C_1)
K - 273.15 = 1(C - 0)
K - 273.15 = C

Therefore, the linear equation relating Celsius temperature to Kelvin temperature is:
K = C + 273.15

\boxed{K = C + 273.15}