Question

Find the indicated probability and interpret the result. From 1975 through​ 2020, the mean annual gain of the Dow Jones Industrial Average was 651. A random sample of 35 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 700​? Assume sigmaequals1540. Question content area bottom Part 1 The probability is    enter your response here. ​(Round to four decimal places as​ needed.)

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Answer to a math question Find the indicated probability and interpret the result. From 1975 through​ 2020, the mean annual gain of the Dow Jones Industrial Average was 651. A random sample of 35 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 700​? Assume sigmaequals1540. Question content area bottom Part 1 The probability is    enter your response here. ​(Round to four decimal places as​ needed.)

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Adonis
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102 Answers
Given:
Population mean ( \mu ) = 651
Population standard deviation ( \sigma ) = 1540
Sample size ( n ) = 35

To find the probability that the mean gain for the sample was between 400 and 700, you need to first calculate the standard error of the mean:
SE = \frac{\sigma}{\sqrt{n}}
SE = \frac{1540}{\sqrt{35}} \approx 260.65

Next, calculate the Z-scores for both 400 and 700:
Z_{400}=\frac{400 - 651}{260.65}\approx-0.964
Z_{700}=\frac{700 - 651}{260.65}\approx0.188

Using a Z-table or calculator, find the probabilities corresponding to these Z-scores:

The answer is:0.4029

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