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find y when y is given by x 7 3

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Find y' when y is given by x^7/3

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Answer to a math question Find y' when y is given by x^7/3

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$y '=\frac{ \mathrm{d} }{ \mathrm{d}x} \left( {x}^{\frac{ 7 }{ 3 }} \right)$

$y '=\frac{ 7 }{ 3 }{x}^{\frac{ 4 }{ 3 }}$

$y '=\frac{ 7x\sqrt[3]{x} }{ 3 }$

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