Question

For his breakfast, Kelvin takes a 75 g bowl of cereal with 150 mL of milk and a 100 mL glass of orange juice. Does this breakfast provide enough kilocalories (kcal)? Representation of the different products: - 30 g of cereals (124 Kcal) - 200 ml of orange juice (98 Kcal) - 100 ml of milk (58 Kcal)

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Answer to a math question For his breakfast, Kelvin takes a 75 g bowl of cereal with 150 mL of milk and a 100 mL glass of orange juice. Does this breakfast provide enough kilocalories (kcal)? Representation of the different products: - 30 g of cereals (124 Kcal) - 200 ml of orange juice (98 Kcal) - 100 ml of milk (58 Kcal)

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Timmothy
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Pour dĂ©terminer si le petit-dĂ©jeuner de Kelvin fournit suffisamment de kilocalories (kcal), nous devons calculer le total des kilocalories fournies par chaque composant de son petit-dĂ©jeuner, puis les rĂ©sumer. DonnĂ©: - 30 g de cĂ©rĂ©ales apportent 124 Kcal - 200 ml de jus d'orange apportent 98 Kcal - 100 ml de lait apportent 58 Kcal Nous devons maintenant ajuster ces valeurs en fonction des quantitĂ©s consommĂ©es par Kelvin. 1. CĂ©rĂ©ales : Kelvin consomme 75 g de cĂ©rĂ©ales. Il faut savoir combien de kilocalories apportent 75 g de cĂ©rĂ©ales : \[ \text{Kcal\_cereals} = \frac{75 \text{ g}}{30 \text{ g}} \times 124 \text{ Kcal} = 3 \times 124 \text{ Kcal} = 372 \text{ Kcal} \] 2. Jus d'orange : Kelvin consomme 100 ml de jus d'orange. Nous devons savoir combien de kilocalories apportent 100 ml de jus d’orange : \[ \text{Kcal\_orange\_juice} = \frac{100 \text{ mL}}{200 \text{ mL}} \times 98 \text{ Kcal} = 0,5 \times 98 \text{ Kcal} = 49 \text{ Kcal} \] 3. Lait : Kelvin consomme 150 ml de lait. Nous devons savoir combien de kilocalories apportent 150 ml de lait : \[ \text{Kcal\_milk} = \frac{150 \text{ mL}}{100 \text{ mL}} \times 58 \text{ Kcal} = 1,5 \times 58 \text{ Kcal} = 87 \text{ Kcal} \] RĂ©sumons maintenant les kilocalories apportĂ©es par chaque composant du petit-dĂ©jeuner : \[ \text{Total\_Kcal} = \text{Kcal\_cĂ©rĂ©ales} + \text{Kcal\_orange\_jus} + \text{Kcal\_lait} \] \[ \text{Total\_Kcal} = 372 \text{ Kcal} + 49 \text{ Kcal} + 87 \text{ Kcal} \] \[ \text{Total\_Kcal} = 508 \text{ Kcal} \] Le total des kilocalories fournies par le petit-dĂ©jeuner de Kelvin est de 508 Kcal. Ce petit-dĂ©jeuner apporte donc suffisamment de kilocalories.

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