How many 4-combinations of the set A=(1,2,3,4,5,6,7,8,9,0) contain 2 and 0?

To find the number of 4-combinations of the set A=(1,2,3,4,5,6,7,8,9,0) that contain both 2 and 0, we can use the combination formula.
The set A contains 10 elements. We need to choose 2 elements from the remaining 8 elements to complete the 4-combination.
So, the number of ways to choose 2 elements from 8 is given by: 2\cdot\binom{8}{2}=56 .Than, multiply it by possible variants of placing 0 and 2: 2*6*56=672

\textbf{Answer:} \boxed{672}