The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: Find the vertex of the parabolic graph y = x^2 - 4x + 3.
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Math question: Solve log base 2 of x minus log base 2 of 4 equals 3
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What is the circumference of a circle with a diameter of 7 units?