The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: What is the value of f(x) when f(x) = 3x^2 - 5x + 2 and x = 4?
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Math question: Find the basis of vectors for a 3-dimensional space given vectors v1 = (1,0,2) and v2 = (2,-1,3).
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Question: What is the limit of (5x^2 + 3x + 4)/(2x^2 - x + 1) as x approaches 3?