The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Question: Simplify (5^3)^2 ÷ (5^2)^3
+
What is the equation for the Pythagorean theorem in geometry?
+
What is the length of the perpendicular bisector to the hypotenuse of a right triangle with legs measuring 3 units each?