The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: What is the amplitude, period, and range of the cosine function f(x) = cos(x)?
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Math Question: Find the coordinates of a point on the ellipse x²/25 + y²/16 = 1 that lies in quadrant II. (
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Math question: What is the result of dividing the fraction 3/5 by the fraction 2/3?