The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: What is the value of log base 3 of 81?
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What are the roots of the cubic equation x^3 + 4x^2 - 11x + 6 = 0?
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Question: What is the limit as x approaches 4 of [(x^2 + 3x - 4) / (x - 4)] + [(3x - 5) / (x - 4)]?