The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: What is the area of a square graph with a side length of 5 units?
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Find the roots of the quadratic equation x^2 - 5x + 6 = 0.