The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math Question: How many ways can you arrange 5 different books on a shelf?
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Find the cosine of ∠A, given that a right triangle ABC with ∠A = 30° and ∠B = 60°.
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What is the value of the constant function f(x) = 7 when x = 5?