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log2 x 5 log5 2x 7

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log2(x-5)=log5(2x+7)

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Answer to a math question log2(x-5)=log5(2x+7)

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The original equation has no solution in the real number domain because there's no value of x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.

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