The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
What is the value of 'a' if the parabola y = ax² has a vertex at (2, 3) and a y-intercept at (0, -4)?
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Question: How many different ways can 5 students be arranged in a line?
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What is the derivative of cos^4(x) + 2sin^3(x) at x = π/6?