The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: Find the equation of the straight line with a slope of 2 and passing through the point (3, 5).
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What is the value of sine of 45 degrees on the unit circle?
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Math question: Find the limit of (3x^2 + 5x + 2)/(4x^2 - 6x + 3) as x approaches 2.