The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Find the period of the trigonometric function y = 3sin(5x) - 2cos(2x) with respect to x in radians.
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Math question: Find the 4th derivative of f(x) = sin(2x) + cos(3x) + e^x at x = π.