The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: Given a right triangle with one leg measuring 15 units and the hypotenuse measuring 17 units, find the length of the other leg.
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Question: Solve the inequality 3x + 5 < 10 for x.
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What is the limit as x approaches 2 of (3x+1)/(x-2)?