The original equation has no solution in the real number domain because there's no value of
x that would make both x−5 and 2x+7 positive at the same time and satisfy the equation.
Frequently asked questions (FAQs)
Math question: Find the hypotenuse of a right triangle with legs measuring 5 cm and 12 cm.
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Question: On the graph of the cosine function f(x) = cos x, what is the amplitude, period, and axis of symmetry?
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Question: Find the product of two consecutive integers, where their sum is 33.