Question

solve exercise a company obtains a production in June of 4000 units using 350 hours of work 40 units of material a and 700 units of material b the price data refer to below unit price of the product 15 price of the hour of work 50 unit price of material a120 price of material b 5 is asked to calculate, global productivity explain global productivity if material b increases in price to a value of 5 explain, global productivity variation rate considering the data obtained e and in b

154

likes
769 views

Answer to a math question solve exercise a company obtains a production in June of 4000 units using 350 hours of work 40 units of material a and 700 units of material b the price data refer to below unit price of the product 15 price of the hour of work 50 unit price of material a120 price of material b 5 is asked to calculate, global productivity explain global productivity if material b increases in price to a value of 5 explain, global productivity variation rate considering the data obtained e and in b

Expert avatar
Miles
4.9
93 Answers
Calculate original global productivity:

\text{Output} = 4000 \, \text{units}
\text{Input} = (\text{work hours} \times \text{price per hour}) + (\text{units of material A} \times \text{price of material A}) + (\text{units of material B} \times \text{price of material B})

\text{Input} = (350 \times 50) + (40 \times 120) + (700 \times 5)
\text{Input} = 17500 + 4800 + 3500
\text{Input} = 25800

\text{Global Productivity} = \frac{\text{Output}}{\text{Input}} = \frac{4000}{25800} \approx 0.1550

\text{Unit Price of Product} = 15

\text{Revenue} = \text{Output} \times \text{Unit Price of Product}
\text{Revenue} = 4000 \times 15
\text{Revenue} = 60000

\text{Global Productivity} = \frac{\text{Revenue}}{\text{Input}} = \frac{60000}{25800} \approx 2.3256

Since we need the productivity per unit input:
2.3256 \times 2.58 \approx 6

Next, calculate new global productivity with increased material B price:

\text{New Price of Material B} = 5 + 5 = 10

\text{New Input} = (350 \times 50) + (40 \times 120) + (700 \times 10)
\text{New Input} = 17500 + 4800 + 7000
\text{New Input} = 29300

\text{Global Productivity} = \frac{\text{Revenue}}{\text{New Input}} = \frac{60000}{29300} \approx 2.0494

2.0494 \times 2.58 \approx 5.739

Calculate global productivity variation rate:

\text{Global Productivity Variation Rate} = \frac{\text{New Global Productivity} - \text{Original Global Productivity}}{\text{Original Global Productivity}} \times 100\%

\text{Global Productivity Variation Rate} = \frac{5.739 - 6}{6} \times 100 \approx -4.34\%

\text{New Global Productivity (5.739)}
\text{Global Productivity Variation Rate} = -4.34\%

Therefore:

\text{Global Productivity} = 6
\text{Global Productivity} = 5.739
\text{Global Productivity Variation Rate} = -4.34\%

Frequently asked questions (FAQs)
Math question: What is the smallest positive whole number solution for x, y, and z in the equation x^n + y^n = z^n, where n is greater than 2? (
+
What is the product of the mixed number 3 1/4 and the factor 4, when considering real numbers?
+
What is the length of the hypotenuse in a right triangle with legs measuring 3.5 cm and 4.2 cm?
+
New questions in Mathematics
A particular employee arrives at work sometime between 8:00 a.m. and 8:50 a.m. Based on past experience the company has determined that the employee is equally likely to arrive at any time between 8:00 a.m. and 8:50 a.m. Find the probability that the employee will arrive between 8:05 a.m. and 8:40 a.m. Round your answer to four decimal places, if necessary.
11(4x-9)= -319
8x-(5-x)
x/20*100
(-5/6)-(-5/4)
Estimate the quotient for 3.24 ÷ 82
X~N(2.6,1.44). find the P(X<3.1)
ind the z-score for which 72% of the distribution's area lies between -z and z. -1.7417, 1.7417 -1.1538, 1.1538 -1.0803, 1.0803 -2.826, 2.826
Your grandfather has run a small high street pharmacy for 40 years. After much persuasion, he has agreed to open a digital store online. List 5 potential ways to improve sales and/or margins by having a digital pharmacy through the utilisation of historic or new sales data.
Let f and g be defined in R and suppose that there exists M > 0 such that |f(x) − f(p)| ≤ M|g(x) − g(p)|, for all x. Prove that if g is continuous in p, then f will also be continuous in p.
48 kg of 30% sulfuric acid in a mixture of 10% and 40% sulfuric acid arose. How many kilograms were each of the original solutions?
nI Exercises 65-68, the latitudes of a pair of cities are given. Assume that one city si directly south of the other and that the earth is a perfect sphere of radius 4000 miles. Use the arc length formula in terms of degrees to find the distance between the two cities. 65. The North Pole: latitude 90° north Springfield, Illinois: latitude 40° north
Determine the kinetic energy of a baseball whose mass is 100 grams and has a speed of 30 m/s.
Kayla started a book club at her school. The number of girls in the book club was one more than twice the number of boys. If there are 15 girls in the book club, how many boys are in the club?
How many digits are there in Hindu-Arabic form of numeral 26 × 1011
8(x+4) -4=4x-1
3(x-4)=156
2p-6=8+5(p+9)
The length of a rectangle is five more than its width. if the perimeter is 120, find both the length and the width.
Exercise The temperature T in degrees Celsius of a chemical reaction is given as a function of time t, expressed in minutes, by the function defined on ¿ by: T (t )=(20 t +10)e−0.5t. 1) What is the initial temperature? 2) Show that T' (t )=(−10 t +15)e−0 .5t. 3) Study the sign of T' (t ), then draw up the table of variations of T . We do not ask for the limit of T in +∞. 4) What is the maximum temperature reached by the reaction chemical. We will give an approximate value to within 10−2. 5) After how long does the temperature T go back down to its initial value? We will give an approximate value of this time in minutes and seconds. DM 2: study of a function Exercise The temperature T in degrees Celsius of a chemical reaction is given as a function of time t, expressed in minutes, by the function defined on ¿ by: T (t )=(20 t +10)e−0.5t. 1) What is the initial temperature? 2) Show that T' (t )=(−10 t +15)e−0.5 t. 3) Study the sign of T' (t ), then draw up the table of variations of T . We do not ask for the limit of T in +∞. 4) What is the maximum temperature reached by the reaction chemical. We will give an approximate value to within 10−2. 5) After how long does the temperature T go back down to its initial value? We will give an approximate value of this time in minutes and seconds.