Answer = The combination formula, denoted as \( \binom{n}{r} \) or \( nCr \), is used to calculate the number of ways to choose \( r \) items from \( n \) items without regard to the order of selection. The formula for \( \binom{n}{r} \) is given by:
\[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]
In this problem, we need to evaluate \( 7C4 \). Plugging \( n = 7 \) and \( r = 4 \) into the formula, we get:
\[\binom{7}{4} = \frac{7!}{4!(7-4)!} = \frac{7!}{4! \cdot 3!}\]
Now, calculate the factorials:
\[7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\]
\[4! = 4 \times 3 \times 2 \times 1\]
\[3! = 3 \times 2 \times 1\]
Substituting these values into the formula, we get:
\[\binom{7}{4} = \frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{(4 \times 3 \times 2 \times 1) \times (3 \times 2 \times 1)}\]
Simplify by canceling the common terms in the numerator and the denominator:
\[\binom{7}{4} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1}\]
Calculate the numerator and the denominator:
\[7 \times 6 \times 5 = 210\]
\[3 \times 2 \times 1 = 6\]
Thus,
\[\binom{7}{4} = \frac{210}{6} = 35\]
Therefore, \( 7C4 = 35 \).