Question
Write the equation of a line in slope intercept form perpendicular to y= -3x+4 passing through the point (-6,6)
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Answer to a math question Write the equation of a line in slope intercept form perpendicular to y= -3x+4 passing through the point (-6,6)
Clarabelle
4.787 Answers
1. Find the slope of the given line, which is -3.
2. The slope of the perpendicular line is the negative reciprocal. So, the new slope is\frac{1}{3}.
3. Use the point-slope form(y - y_1 = m(x - x_1)) \frac{1}{3}.
y - 6 = \frac{1}{3}(x + 6)
4. Distribute the slope:
y - 6 = \frac{1}{3}x + 2
5. Add 6 to both sides to get the slope-intercept form:
y = \frac{1}{3}x + 8
Final answer:y = \frac{1}{3}x + 8
2. The slope of the perpendicular line is the negative reciprocal. So, the new slope is
3. Use the point-slope form
4. Distribute the slope:
5. Add 6 to both sides to get the slope-intercept form:
Final answer:
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