Question

Write the equation of a line in slope intercept form perpendicular to y= -3x+4 passing through the point (-6,6)

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Clarabelle

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84 Answers

1. Find the slope of the given line, which is -3.

2. The slope of the perpendicular line is the negative reciprocal. So, the new slope is\frac{1}{3}.

3. Use the point-slope form(y - y_1 = m(x - x_1)) with the point $(-6, 6)$ and slope \frac{1}{3}.

y - 6 = \frac{1}{3}(x + 6)

4. Distribute the slope:

y - 6 = \frac{1}{3}x + 2

5. Add 6 to both sides to get the slope-intercept form:

y = \frac{1}{3}x + 8

Final answer:y = \frac{1}{3}x + 8

2. The slope of the perpendicular line is the negative reciprocal. So, the new slope is

3. Use the point-slope form

4. Distribute the slope:

5. Add 6 to both sides to get the slope-intercept form:

Final answer:

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