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Solved equation

y=2cos (x+4)
Theta=arccos ((9)/(15))
4x^2-5x=3
15xw^8n^5,8y^1 0wm^7
y=sin (5x)
480=((1)/(3))(6)(h)
5*x^2*y^2-23*x*y^2
log(3x-7^2)/log(4)=10
12x+15=(4x+5)
L=6((1)/(4))in+11((7)/(8))in+(1)/(2)((1)/(4))in