# MathMaster Blog

Long addition is used to add large numbers by combining two numbers into a single quantity, called a sum.

## How to do the long addition:

• Step 1: Write the numbers you want to add, one underneath the other.
• Step 2: Add up the numbers in the right-most column.
• Step 3: Check if the answer from the previous step is 9 or less:

if yes, write the number below the column $between the lines$ and move to Step 4.

if no, the answer will have two digits. Write the digit on the right under the column $between the lines$. Write the digit on the left under the column to the left of the current column $below the two lines$. Move to Step 4.

• Step 4: Move to the column to the left. Add up the numbers in this column, including any numbers below the two lines.
• Step 5: Go to Step 3 and repeat until all columns have been added.

### Solution:

Step1:

Add up the numbers in the right-most column.

7 + 4 = 11

Step2:

Check if the answer from the previous step is 9 or less:

11 is not 9 or less, so the answer will have two digits. Write the digit on the right under the column $between the lines$.

Write the digit on the left underneath the column to the left of the current column $below the two lines$.

‘Carry’ the 1. Move to the next step.

Step3:

Move to the column to the left. Add up the numbers in this column, including any numbers below the two lines.

Step4:

Now, you have to repeat the algorithm until all the columns are added up.

Check if the answer from the previous step is 9 or less.

No. 11 is not 9 or less. So, write the digit on the right underneath the column $between the lines$.

Write the digit on the left underneath the column to the left of the current column $below the two lines$.

‘Carry’ the 1. Move to the next step.

Step5:

Move to the column to the left. Add up the numbers in this column, including any numbers below the two lines.

3 + 1 + 1 = 5

Step6:

Check if the answer from the previous step is 9 or less. As 5 is less than 9, write the number below the column $between the lines$: