1. Start with the given equations:
2x + 3y = 9
3x - y = 8
2. To eliminate \( y \), multiply the second equation by 3:
9x - 3y = 24
3. Add the modified second equation to the first equation:
(2x + 3y) + (9x - 3y) = 9 + 24
11x = 33
4. Solve for \( x \):
x = \frac{33}{11}
x = 3
5. Substitute \( x = 3 \) into the second original equation:
3(3) - y = 8
9 - y = 8
6. Solve for \( y \):
y = 9 - 8
y = 1
7. The solution is:
x = 3, \, y = 1