3. Due to the force of gravity, a 15.0 kg wooden crate slides down a steel ramp with an incline of 25.0°. Compute the acceleration of the crate down the incline. The coefficient of kinetic friction is 0.300.

1. Calculate the gravitational force component down the ramp:
F_{\text{gravity}} = 15.0 \cdot 9.81 \cdot \sin(25.0^\circ) = 62.08 \, \text{N}

2. Calculate the normal force:
F_{\text{normal}} = 15.0 \cdot 9.81 \cdot \cos(25.0^\circ) = 133.39 \, \text{N}

3. Find the frictional force:
F_{\text{friction}} = 0.300 \cdot 133.39 = 40.02 \, \text{N}

4. Determine the net force down the ramp:
F_{\text{net}} = 62.08 - 40.02 = 22.06 \, \text{N}

5. Calculate the acceleration:
a = \frac{22.06}{15.0} = 1.47 \, \text{m/s}^2

Thus, the acceleration of the crate down the incline is approximately 1.47 \, \text{m/s}^2 . (Please note that the original solution provided had an incorrect calculation. The correct acceleration should be 1.47 \, \text{m/s}^2 .)