Question

a car travels due east with a speed of 30.0 km/h. Rain drops are falling at a constant speed celocity with respect to the earth. The traces of the rain on the side windows of the car make an angle of 42.0 degrees with the vertical. Find the velocity of the rain with respect to the car and the earth. (Enter the magnitude of the velocity.) (a) the car in km/h (B) the Earth in km/h

118

likes
589 views

Answer to a math question a car travels due east with a speed of 30.0 km/h. Rain drops are falling at a constant speed celocity with respect to the earth. The traces of the rain on the side windows of the car make an angle of 42.0 degrees with the vertical. Find the velocity of the rain with respect to the car and the earth. (Enter the magnitude of the velocity.) (a) the car in km/h (B) the Earth in km/h

Expert avatar
Frederik
4.6
101 Answers
To find the velocity of the rain with respect to the car, we can use trigonometry. Let's assume the velocity of the rain with respect to the car is v_{\text{rain-car}} and the velocity of the car is v_{\text{car}}.

Using the angle of 42.0 degrees, we can write the following equation:

\tan(42.0^\circ) = \frac{{v_{\text{rain-car}}}}{{v_{\text{car}}}}

Now, let's solve for v_{\text{rain-car}}:

v_{\text{rain-car}} = v_{\text{car}} \cdot \tan(42.0^\circ)

Substituting the given value v_{\text{car}} = 30.0 \, \text{km/h} into the equation gives:

v_{\text{rain-car}} = 30.0 \, \text{km/h} \cdot \tan(42.0^\circ)

Now, we can use a calculator to evaluate this expression:

v_{\text{rain-car}} \approx 30.0 \, \text{km/h} \cdot 0.900404044 \approx 27.012 \, \text{km/h}

Therefore, the velocity of the rain with respect to the car is approximately 27.012 km/h.

To find the velocity of the rain with respect to the Earth, we can use the concept of relative velocity. Since the car is traveling due east, the velocity of the car with respect to the Earth is v_{\text{car}} = 30.0 \, \text{km/h} towards the east.

The velocity of the rain with respect to the Earth can be found by adding the velocity of the rain with respect to the car and the velocity of the car with respect to the Earth:

v_{\text{rain-earth}} = v_{\text{rain-car}} + v_{\text{car}}

Substituting the values gives:

v_{\text{rain-earth}} = 27.012 \, \text{km/h} + 30.0 \, \text{km/h}

Simplifying this equation gives:

v_{\text{rain-earth}} = 57.012 \, \text{km/h}

Therefore, the velocity of the rain with respect to the Earth is 57.012 km/h.

Answer:
(a) The velocity of the rain with respect to the car is approximately 27.012 km/h.
(b) The velocity of the rain with respect to the Earth is 57.012 km/h.

Frequently asked questions (FAQs)
What is the value of sinh(5) - cosh(3)?
+
What is the median of a set of numbers {2, 5, 7, 9, 15, 20}?
+
What is the median of the set {12, 14, 19, 22, 26, 30, 36}?
+
New questions in Mathematics
Solution of the equation y'' - y' -6y = 0
Let the vectors be u=(-1,0,2) , v=(0,2,-3) , w=(2,2,3) Calculate the following expressions a)<u,w> b) &lt;2u- 5v,3w&gt;
A circle with a 12-inch diameter is folded in half and then folded in half again. What is the area of the resulting shape?
two particles start at the origin and move along the x axis. for 0 <= t <= 10, their respective position functions are given by x1 = cos(t) and x2 = (e^-3t) + 1. for how many values of t do the particles have the same velocity?
You have been hired to estimate the average weight of quarters in circulation. Based on the sample of quarters you collect (below), create a 90% confidence interval for the weight of quarters in circulation. Quarter Weights (grams) 5.631 5.714 5.719 5.689 5.551 5.723 5.705 5.627 5.627 5.715 5.576 5.632 5.641 5.676 5.660 5.699 5.609 5.634 5.713 5.591 5.674 5.675 5.684 5.694 5.655 5.632 5.598 5.675 5.628 5.562 5.636 5.583 5.567 5.551 5.649 5.708 5.696 5.614 5.637 5.601 5.628 5.711 5.566 5.653 5.653 5.597 5.687 5.717 5.678 5.654 5.556 5.707 5.563 5.628 5.679 5.714 5.555 5.719 5.634 5.647 5.717 5.612 5.705 5.657 5.670 5.607 5.687 5.666 5.612 5.718 5.714 5.713 5.663 5.641 5.589 5.656 5.712 5.639 5.577 5.580 5.674 5.636 5.625 5.597 5.616 5.591 5.616 5.700 5.706 5.695 5.562 5.699 5.607 5.573 5.659 5.632 5.654 5.568 5.628 5.687 5.605 5.689 5.687 5.554 5.618 5.701 5.681 5.645 5.714 5.665 5.661 5.634 5.714 5.586 5.656 5.673 5.657 5.717 5.611 5.578 5.579 5.614 5.644 5.724 5.647 5.566 5.697 5.558 5.586 5.586 5.611 5.573 5.573 5.709 5.629 5.649 5.552 5.615 5.645 5.611 5.686 5.588 5.641 5.704 5.703 5.696 5.557 5.551 5.725 5.608 5.725 5.603 5.677 5.638 5.573 5.640 5.561 5.631 5.563 5.671 5.662 5.569 5.648 5.680 5.681 5.551 5.555 5.578 5.701 5.645 5.670 5.574 5.594 5.705 5.633 5.719 5.680 5.647 5.641 5.553 5.616 5.698 5.552 5.566 5.559 5.697 5.686 5.560 5.629 5.701 5.622 5.615 5.553 5.608 5.637 5.663 5.696 5.714 5.675 5.613 5.594 5.669 5.569 5.716 5.705 5.603 5.709 5.717 5.606 5.581 5.575 5.601 5.600 5.664 5.715 5.705 5.583 5.586 5.592 5.550 5.628 5.662 5.603 5.559 5.676 5.558 5.678 5.671 5.642 5.581 5.568 5.706 5.665 5.712 5.574 5.602 5.699 5.716 5.693 5.711 5.635 5.612 BLANK #1: Is this a question involving mean or proportion? ***ANSWER "MEAN" OR "PROPORTION" (WITHOUT THE QUOTATION MARKS)*** BLANK #2: What is the LOW end of the estimate ***ANSWER TO 3 DECIMALS*** BLANK #3: What is the HIGH end of the estimate ***ANSWER TO 3 DECIMALS***
Estimate the fifth term if the first term is 8 and the common ratio is -1/2
4. Show that if n is any integer, then n^2 3n 5 is an odd integer
Substitute a=2 and b=-3 and c=-4 to evaluate 2ac/(-2b^2-a)
12(3+7)-5
3+7
The question is using rule 72 determine Kari wants to save 10,000 for a down payment on a house. Illustrate the difference in years it will take her to double her current 5,000 savings based on 6%, 12% and 18% interest rate .
3%2B2
Show work on 4108 divided by 4
(6²-14)÷11•(-3)
On Tuesday Shanice bought five hats.On Wednesday half of all the hats that she had were destroyed.On Thursday there were only 17 left.How many Did she have on Monday.
Let G be the center of gravity of triangle ABC. We draw through A a parallel to BC on which we take a point D so that DG⊥BG. If the area of the quadrilateral AGBD is equal to s, show that AC·BD≥2·s.
The average weekly earnings in the leisure and hospitality industry group for a re‐ cent year was $273. A random sample of 40 workers showed weekly average ear‐ nings of $285 with the population standard deviation equal to 58. At the 0.05 level of significance can it be concluded that the mean differs from $273? Find a 95% con‐ fidence interval for the weekly earnings and show that it supports the results of the hypothesis test.
2 - 6x = -16x + 28
1. The cost to transport 250 packages of cement 120 kilometers is $600. What will be the cost to transport 500 packages 300 kilometers?
A membership to the gym cost $25 per person in 1995. The membership cost has increased by an average $6 per person for each year since 1995. Write a linear equation for the cost of a gym membership for one person since 1995. What is the cost of a gym membership in 2009?