Question

A chunk of ice breaks off a glacier and falls 10.0 m before it hits the water. Assuming it falls freely (there is no air resistance), how long does it take to hit the Water

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Neal

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72 Answers

1. Use the formula for distance in uniformly accelerated motion:

s = \frac{1}{2} g t^2

2. Rearrange the formula to solve for \( t \):

t^2 = \frac{2s}{g}

3. Take the square root of both sides:

t = \sqrt{\frac{2s}{g}}

4. Substitute the given values:

t = \sqrt{\frac{2 \times 10.0 \, \text{meters}}{9.8 \, \text{m/s}^2}}

5. Calculate:

t = \sqrt{\frac{20.0 \, \text{meters}}{9.8 \, \text{m/s}^2}}

6. Simplify and take the square root:

t = \sqrt{2.04}

7. Approximately:

t \approx 1.43 \, \text{seconds}

The answer is:

t \approx 1.43 \, \text{seconds}

2. Rearrange the formula to solve for \( t \):

3. Take the square root of both sides:

4. Substitute the given values:

5. Calculate:

6. Simplify and take the square root:

7. Approximately:

The answer is:

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