A chunk of ice breaks off a glacier and falls 10.0 m before it hits the water. Assuming it falls freely (there is no air resistance), how long does it take to hit the Water

1. Use the formula for distance in uniformly accelerated motion:
s = \frac{1}{2} g t^2

2. Rearrange the formula to solve for \( t \):
t^2 = \frac{2s}{g}

3. Take the square root of both sides:
t = \sqrt{\frac{2s}{g}}

4. Substitute the given values:
t = \sqrt{\frac{2 \times 10.0 \, \text{meters}}{9.8 \, \text{m/s}^2}}

5. Calculate:
t = \sqrt{\frac{20.0 \, \text{meters}}{9.8 \, \text{m/s}^2}}

6. Simplify and take the square root:
t = \sqrt{2.04}

7. Approximately:
t \approx 1.43 \, \text{seconds}

The answer is:

t \approx 1.43 \, \text{seconds}