a messenger in a company collected an interest free loan of #93,000 from the company which should be withdrawn from his salary in 12 months if #5,000 is withdrawn from the 1st month and the amount to be withdrawn increase each month by equal amount of the preceeding month. How much will be withdrawn from his salary in the last month?

To find out how much will be withdrawn from the messenger's salary in the last month, we need to calculate the increasing amount each month.

In this scenario, the amount to be withdrawn each month follows an arithmetic progression, with a common difference of #5,000.

To find the amount to be withdrawn in the last month, we need to find the 12th term of the arithmetic progression.

The formula to find the nth term of an arithmetic progression is given by:

a_n = a + (n - 1)d

Where:
- a is the first term of the progression
- n is the term number we are looking for
- d is the common difference

In this case:
- a = 5000 (first term, amount withdrawn from the 1st month)
- n = 12 (we are looking for the 12th month)
- d = 5000 (common difference, each month's amount increases by #5,000)

Substituting the values into the formula, we get:

a_{12} = 5000 + (12 - 1) \cdot 5000

Simplifying further:

a_{12} = 5000 + 11 \cdot 5000

a_{12} = 5000 + 55000

a_{12} = 60000

Therefore, #60,000 will be withdrawn from the messenger's salary in the last month.

Answer: \boxed{60000}.