1. Identify that \( V_p = 300\,V \) and the angle is \( 30^\circ \).
2. Recall that instantaneous voltage is given by 
    v = V_p \sin(\theta) 
3. Substitute the known values into the formula:
    v = -300 \sin(30^\circ) 
4. Solve for sine of \( 30^\circ \) (which is \( 0.5 \)):
    v = -300 \times 0.5 
5. Calculate the result:
    v = -150\,V 
6. Answer is:
    -150\,V