Respuesta :
y = -8x + 7
Solución:
ecuación de una recta que pasa por el punto (x1, y1) y pendiente m:
y-y1 = m (x - x1)
pendiente m = -8
(x1, y1) = (2, -9)
y- (-9) = -8 (x -2)
y+ 9 = -8x + 16
y = -8x + 16 -9
y = -8x + 7
Frequently asked questions (FAQs)
What is the value of cos(pi/3) - tan(pi/4) * sin(3pi/2) in the trigonometric table?
+
Find the period, amplitude, and phase shift of the tangent function f(x) = tan x. (