Question

Dilute the IgG protein standard (200 µg/mL) to create a 6-point standard curve ranging from 0 – 75 µg/mL (in duplicate). Determine the valid concentrations for each tube. The final volume is 1.0 mL. Table 1. Preparation of IgG standard curve including volumes, concentrations, and absorbance values determined by undertaking a Bradford assay (2 mark). Tube 1 2 3 4 5 6 7 8 9 10 11 12 IgG (200 µg/mL), mL H2O, mL Final [IgG] (µg/mL) 0 0 75 75

84

likes
421 views

Answer to a math question Dilute the IgG protein standard (200 µg/mL) to create a 6-point standard curve ranging from 0 – 75 µg/mL (in duplicate). Determine the valid concentrations for each tube. The final volume is 1.0 mL. Table 1. Preparation of IgG standard curve including volumes, concentrations, and absorbance values determined by undertaking a Bradford assay (2 mark). Tube 1 2 3 4 5 6 7 8 9 10 11 12 IgG (200 µg/mL), mL H2O, mL Final [IgG] (µg/mL) 0 0 75 75

Expert avatar
Cristian
4.7
119 Answers
To prepare a 6-point standard curve ranging from 0 – 75 µg/mL using the 200 µg/mL IgG protein standard, we will dilute it with water (H2O) to create the desired concentrations in each tube.

Let's denote:
- V1 as the volume of 200 µg/mL IgG protein standard required in each tube (in mL).
- V2 as the volume of water (H2O) required in each tube (in mL).
- C1 as the initial concentration of IgG protein standard (200 µg/mL).
- C2 as the final concentration of IgG protein standard in the tubes (ranging from 0 – 75 µg/mL).
- V_total as the final volume of each tube (1.0 mL).

Given that:
- Tube 1 and 2 will have 0 µg/mL IgG.
- Tube 11 and 12 will have 75 µg/mL IgG.

We can set up a proportion to calculate the volumes of the 200 µg/mL IgG protein standard and water needed in each tube:

For Tube 1 and 2 (0 µg/mL IgG):
\frac{V1}{1.0} = \frac{0}{200} \Rightarrow V1 = 0 \, \text{mL}
V2 = 1.0 - V1 = 1.0 \, \text{mL}

For each tube from 3 to 10 (intermediate concentrations):
\frac{V1}{1.0} = \frac{C2}{C1}
V1 = \frac{C2}{C1} \times 1.0
V2 = 1.0 - V1

For Tube 11 and 12 (75 µg/mL IgG):
\frac{V1}{1.0} = \frac{75}{200} \Rightarrow V1 = 0.375 \, \text{mL}
V2 = 1.0 - V1 = 0.625 \, \text{mL}

Therefore, valid concentrations for each tube are:
- Tube 1: 0 µg/mL IgG (0 mL of 200 µg/mL IgG standard, 1.0 mL H2O)
- Tube 2: 0 µg/mL IgG (0 mL of 200 µg/mL IgG standard, 1.0 mL H2O)
- Tube 3 to 10: Concentrations ranging between 0.0 µg/mL to 75 µg/mL
- Tube 11: 75 µg/mL IgG (0.375 mL of 200 µg/mL IgG standard, 0.625 mL H2O)
- Tube 12: 75 µg/mL IgG (0.375 mL of 200 µg/mL IgG standard, 0.625 mL H2O)

\boxed{\text{Answer: Valid concentrations for each tube have been determined.}}

Frequently asked questions (FAQs)
What is 2.5 radians in degrees?
+
Find the period of the trigonometric function f(x) = 3sin(2x) - cos(4x).
+
What is the derivative of f(x) = e^(2x)sin(3x) - ln(x^2)cos(4x), where e is the base of the natural logarithm?
+
New questions in Mathematics
(x^2+3x)/(x^2-9)=
1 plus 1
The bus one way of the road which is 10km is heading with speed of 20km/h ,then the bus the other 10km is heading with speed of 60km/h. The middle speed of the road is it equal with arithmetic speed of the v1 and v2 ?
If eight basketball teams participate in a tournament, find the number of different ways that first, second, and third places can be decided assuming that no ties are allowed.
If f(x,y)=6xy^2+3y^3 find (∫3,-2) f(x,y)dx.
Substitute a=2 and b=-3 and c=-4 to evaluate 2ac/(-2b^2-a)
show step by step simplification: (¬𝑑∨((¬b∧c)∨(b∧¬c)))∧((𝑎 ∧ 𝑏) ∨ (¬𝑎 ∧ ¬𝑏))∧(¬𝑐∨((¬𝑑∧𝑎)∨(𝑑∧¬𝑎)))
In a order to compare the means of two populations, independent random samples of 410 observations are selected from each population, with Sample 1 the results found in the table to the right. Complete parts a through e below. X1 = 5,319 S1= 143 a. Use a 95% confidence interval to estimate the difference between the population means (H - H2) Interpret the contidence interval. The contidence interval IS (Round to one decimal place as needed.) Sample 2 X2 = 5,285 S2 = 198 Aa. Use a 95% confidence interval to estimate the difference between the population means (A1 - M2) Interpret the contidence interval. The contidence interval Is (Round to one decimal place as needed.) b. Test the null hypothesis Ho versus alternative hypothesis Ha (H What is the test statistic? H2) + Give the significance level of the test, and interpret the result. Use a = 0.05. Z=
A stunt man jumps horizontally from a building to the roof of a garage that is 2 meters lower. How fast does he need to be to land on the roof of the said garage that is 3 meters away from the building?
3 A tree is planted when it is 1.2 m tall. Every year its growth is 3/8 of its previous year's height. Find how tall the tree will grow.
P(Z<z)=0.1003
Find the center coordinates and radius of a circle for an equation written as: 3x2 + 3y2 - 6y = —12× + 24
7.57 Online communication. A study suggests that the average college student spends 10 hours per week communicating with others online. You believe that this is an underestimate and decide to collect your own sample for a hypothesis test. You randomly sample 60 students from your dorm and find that on average they spent 13.5 hours a week communicating with others online. A friend of yours, who offers to help you with the hypothesis test, comes up with the following set of hypotheses. Indicate any errors you see. H0 :x ̄<10hours HA : x ̄ > 13.5 hours
48 kg of 30% sulfuric acid in a mixture of 10% and 40% sulfuric acid arose. How many kilograms were each of the original solutions?
-5x=115
How many cards do you expect to pull from a poker deck until you get an ACE?
If sin A=0.3 and cos A=0.6, determine the value of tan A.
A membership to the gym cost $25 per person in 1995. The membership cost has increased by an average $6 per person for each year since 1995. Write a linear equation for the cost of a gym membership for one person since 1995. What is the cost of a gym membership in 2009?
write in set builder notation { 1,3,9,27,81,243,...}
A plant found at the bottom of a lake doubles in size every 10 days. Yeah It is known that in 300 days it has covered the entire lake, indicate how many days it will take to cover the entire lake four similar plants.