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Factor completely N^2-5n+4

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Answer to a math question Factor completely N^2-5n+4

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${n}^{2}-n-4n+4$

$n \times \left( n-1 \right)-4n+4$

$n \times \left( n-1 \right)-4\left( n-1 \right)$

$\left(n-1\right)\left(n-4\right)$

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