Find the smallest two consecutive integers such that five times the smaller is at least eight more than three the larger

Set up the expression for the problem: 5x \geq 3(x+1) + 8

2. Distribute and simplify: 5x \geq 3x + 3 + 8

3. Combine like terms: 5x \geq 3x + 11

4. Isolate the variable: 2x \geq 11

5. Solve for the smallest integer: x \geq 5.5 , so the smallest integer is 6.

6. The integers are 6 and 7.

7. Answer: (6, 7)