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Find the smallest two consecutive integers such that five times the smaller is at least eight more than three the larger

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Answer to a math question Find the smallest two consecutive integers such that five times the smaller is at least eight more than three the larger

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Bud

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1. Let x be the smallest integer,

Set up the expression for the problem:

5x \geq 3(x+1) + 8

2. Distribute and simplify:

5x \geq 3x + 3 + 8

3. Combine like terms:

5x \geq 3x + 11

4. Isolate the variable:

2x \geq 11

5. Solve for the smallest integer:

x \geq 5.5

, so the smallest integer is 6.

6. The integers are 6 and 7.

7. Answer: (6, 7)

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Find the smallest two consecutive integers such that five times the smaller is at least eight more than three the larger

Answer to a math question Find the smallest two consecutive integers such that five times the smaller is at least eight more than three the larger

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