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find two consecutive integers such that four times the larger is 94 more than three times the smaller

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Find two consecutive integers such that four times the larger is 94 more than three times the smaller

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Answer to a math question Find two consecutive integers such that four times the larger is 94 more than three times the smaller

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1. Let the two consecutive integers be \( x \) and \( x + 1 \).
2. According to the problem, four times the larger integer is 94 more than three times the smaller integer. Therefore, the expression becomes:

4(x + 1) = 3x + 94

3. Distribute and simplify:

4x + 4 = 3x + 94

4. Subtract \( 3x \) from both sides:

x + 4 = 94

5. Subtract 4 from both sides:

x = 90

6. The larger integer is:

x + 1 = 90 + 1 = 91

Answer: The larger integer is 91, so the consecutive integers are 90 and 91.

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