Let's first find out how much each student contributed in their group.
Let x be the amount each student contributes in their group.
For group 1A with 31 students, the total contribution is 31x = 956 . So, x = \frac{956}{31} .
For group 1B with 34 students, the total contribution is 34x = 956 . So, x = \frac{956}{34} .
For group 2A with 20 students, the total contribution is 20x = 956 . So, x = \frac{956}{20} .
For group 2B with 22 students, the total contribution is 22x = 956 . So, x = \frac{956}{22} .
For group 3A with 18 students, the total contribution is 18x = 956 . So, x = \frac{956}{18} .
For group 3B with 24 students, the total contribution is 24x = 956 . So, x = \frac{956}{24} .
Now, let's find out the percentage each student contributed in their group. Since each student contributed the same amount in their group, we will use the values of x calculated for each group.
The percentage each student contributed in their group is given by:
\left( \frac{x}{956} \right) \times 100 \%
Now, let's calculate the total amount raised by the entire school.
Total amount raised = 1A + 1B + 2A + 2B + 3A + 3B = 6 \times 956
### Answer
1. Each student contributes:
- Group 1A: \frac{956}{31}=30.84 dollars
- Group 1B: \frac{956}{34}=28.12 dollars
- Group 2A: \frac{956}{20}=47.8 dollars
- Group 2B: \frac{956}{22}=43.45 dollars
- Group 3A: \frac{956}{18}=53.11 dollars
- Group 3B: \frac{956}{24}=39.83 dollars
2. The percentage each student contributed in their group:
- Group 1A: \left(\frac{956}{31 \times956}\right)\times100\%=3.23\%
- Group 1B: \left(\frac{956}{34 \times956}\right)\times100\%=2.94\%
- Group 2A: \left(\frac{956}{20 \times956}\right)\times100\%=5\%
- Group 2B: \left(\frac{956}{22 \times956}\right)\times100\%=4.55\%
- Group 3A: \left(\frac{956}{18 \times956}\right)\times100\%=5.56\%
- Group 3B: \left(\frac{956}{24 \times956}\right)\times100\%=4.17\%
3. Total amount raised by the entire school: 6 \times 956 = 5736 dollars