Question
Let f(x) =x^2-6x+4 Solve for f(x-3)=
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Answer to a math question Let f(x) =x^2-6x+4 Solve for f(x-3)=
Jayne
4.496 Answers
1. Substitute \( x-3 \) for \( x \) in the function \( f(x) \):
f(x-3) = (x-3)^2 - 6(x-3) + 4
2. Expand and simplify the squared term:
(x-3)^2 = x^2 - 6x + 9
3. Then distribute the -6:
-6(x-3) = -6x + 18
4. Substitute these into the equation:
f(x-3) = x^2 - 6x + 9 - 6x + 18 + 4
5. Combine like terms:
f(x-3) = x^2 -12x + 31
So the answer is:
f(x-3) = x^2 - 12x + 31
2. Expand and simplify the squared term:
3. Then distribute the -6:
4. Substitute these into the equation:
5. Combine like terms:
So the answer is:
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