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sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?

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Answer to a math question sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?

Expert avatar
Clarabelle
4.7
94 Answers
Let's denote Brad's current weight as x lbs.

According to the problem, Sean weighs 10 lbs more than twice Brad's weight, so Sean's current weight is 2x + 10 lbs.

If Brad gains 10 lbs, his weight will be x + 10 lbs.

Together, Brad and Sean weigh 230 lbs, so we have the equation:
x+10+(2x+10)=230

Solving for x :
3x+20=230
3x=210
x=\frac{210}{3}
x=70\text{ lbs}

So, Brad's current weight is approximately 70 lbs.

Plugging this back into the expression for Sean's weight:
2(70\overline{})+10=2\times70\overline{}+10=150\text{ lbs}

Therefore, Brad currently weighs approximately 73.3 lbs and Sean currently weighs approximately 156.6 lbs.

\boxed{\text{Brad: 70 lbs, Sean: 150 lbs}}

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