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sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?

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Answer to a math question sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?

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Clarabelle

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94 Answers

Let's denote Brad's current weight as

lbs.

According to the problem, Sean weighs 10 lbs more than twice Brad's weight, so Sean's current weight is

2x + 10

lbs.

If Brad gains 10 lbs, his weight will be

x + 10

lbs.

Together, Brad and Sean weigh 230 lbs, so we have the equation:

x+10+(2x+10)=230

Solving for

3x+20=230

3x=210

x=\frac{210}{3}

x=70\text{ lbs}

So, Brad's current weight is approximately 70 lbs.

Plugging this back into the expression for Sean's weight:

2(70\overline{})+10=2\times70\overline{}+10=150\text{ lbs}

Therefore, Brad currently weighs approximately 73.3 lbs and Sean currently weighs approximately 156.6 lbs.

\boxed{\text{Brad: 70 lbs, Sean: 150 lbs}}

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sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?

Answer to a math question sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?

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