Question
sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?
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Answer to a math question sean weighs 10 lb more than twice brads weight. if brad gains 10 lb, together they’ll weigh 230 lb. how much does each weigh now?
Clarabelle
4.793 Answers
Let's denote Brad's current weight as x
According to the problem, Sean weighs 10 lbs more than twice Brad's weight, so Sean's current weight is2x + 10
If Brad gains 10 lbs, his weight will bex + 10
Together, Brad and Sean weigh 230 lbs, so we have the equation:
x+10+(2x+10)=230
Solving forx
3x+20=230
3x=210
x=\frac{210}{3}
x=70\text{ lbs}
So, Brad's current weight is approximately 70 lbs.
Plugging this back into the expression for Sean's weight:
2(70\overline{})+10=2\times70\overline{}+10=150\text{ lbs}
Therefore, Brad currently weighs approximately 73.3 lbs and Sean currently weighs approximately 156.6 lbs.
\boxed{\text{Brad: 70 lbs, Sean: 150 lbs}}
According to the problem, Sean weighs 10 lbs more than twice Brad's weight, so Sean's current weight is
If Brad gains 10 lbs, his weight will be
Together, Brad and Sean weigh 230 lbs, so we have the equation:
Solving for
So, Brad's current weight is approximately 70 lbs.
Plugging this back into the expression for Sean's weight:
Therefore, Brad currently weighs approximately 73.3 lbs and Sean currently weighs approximately 156.6 lbs.
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